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    spring boot jpa findById查询问题
    29
    0

    代码

    package com.spring.controller;
    
    import java.util.List;
    
    import org.springframework.data.jpa.repository.Query;
    import org.springframework.data.repository.CrudRepository;
    import org.springframework.stereotype.Repository;
    
    //@Repository
    public interface UserRepository extends CrudRepository<User, Integer> {
        
        @Query("select id,name from users where id=:id")
        List<User> findById(Integer id);
    
    }
    
    package com.spring.controller;
    
    import javax.persistence.*;
    
    
    @Entity
    @Table(name = "users")
    public class User {
        
        @Id
        @GeneratedValue(strategy = GenerationType.AUTO)
        private Integer Id;
        private String name;
    
        public User () {}
        
        public User(Integer Id, String name) {
            this.Id = Id;
            this.name = name;
        }
    
        public Integer getId() {
            return Id;
        }
    
        public void setId(Integer id) {
            Id = id;
        }
    
        public String getName() {
            return name;
        }
    
        public void setName(String name) {
            this.name = name;
        }
    
    }
    
    spring.jpa.hibernate.ddl-auto=update
    spring.datasource.url=jdbc:mysql://localhost:3306/test?SSL=false
    spring.datasource.username=root
    spring.datasource.password=123456
    
    <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
      xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
      <modelVersion>4.0.0</modelVersion>
      <groupId>com.test</groupId>
      <artifactId>spring</artifactId>
      <packaging>war</packaging>
      <version>0.0.1-SNAPSHOT</version>
      <name>spring Maven Webapp</name>
      <url>http://maven.apache.org<;/url>
    
    <parent>
      <groupId>org.springframework.boot</groupId>
      <artifactId>spring-boot-starter-parent</artifactId>
      <version>1.4.3.RELEASE</version>
    </parent>
    
    <properties>
        <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
        <java.version>1.8</java.version>
        <springBoot.groupId>org.springframework.boot</springBoot.groupId>
    </properties>
    
    
    
    
    
    
    
      <dependencies>
    
    
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-web</artifactId>
    </dependency>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-data-jpa</artifactId>
    </dependency>
    <dependency>
        <groupId>mysql</groupId>
        <artifactId>mysql-connector-java</artifactId>
        <scope>runtime</scope>
    </dependency>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-test</artifactId>
        <scope>test</scope>
    </dependency>
    <dependency>
        <groupId>com.alibaba</groupId>
        <artifactId>fastjson</artifactId>
        <version>1.2.7</version>
    </dependency>
    
    
    
    
    
        <dependency>
          <groupId>junit</groupId>
          <artifactId>junit</artifactId>
          <version>3.8.1</version>
          <scope>test</scope>
        </dependency>
        <dependency>
            <groupId>org.hibernate</groupId>
            <artifactId>hibernate-jpamodelgen</artifactId>
        </dependency>
      </dependencies>
    
    
    
    <build>
        <plugins>
            <plugin>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-maven-plugin</artifactId>
            </plugin>
        </plugins>
    </build>
    
    
    </project>
    

    报错

    
    Error starting ApplicationContext. To display the auto-configuration report re-run your application with 'debug' enabled.
    2018-07-03 09:27:45.588 ERROR 2792 --- [           main] o.s.boot.SpringApplication               : Application startup failed
    
    org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'controller1': Unsatisfied dependency expressed through field 'userRepository'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userRepository': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Validation failed for query for method public abstract java.util.List com.spring.controller.UserRepository.findById(java.lang.Integer)!
        at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:588) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.annotation.InjectionMetadata.inject(InjectionMetadata.java:88) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor.postProcessPropertyValues(AutowiredAnnotationBeanPostProcessor.java:366) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1225) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:552) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:483) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:306) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:230) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:302) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:197) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:759) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:866) ~[spring-context-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:542) ~[spring-context-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.boot.context.embedded.EmbeddedWebApplicationContext.refresh(EmbeddedWebApplicationContext.java:122) ~[spring-boot-1.4.3.RELEASE.jar:1.4.3.RELEASE]
        at org.springframework.boot.SpringApplication.refresh(SpringApplication.java:761) [spring-boot-1.4.3.RELEASE.jar:1.4.3.RELEASE]
        at org.springframework.boot.SpringApplication.refreshContext(SpringApplication.java:371) [spring-boot-1.4.3.RELEASE.jar:1.4.3.RELEASE]
        at org.springframework.boot.SpringApplication.run(SpringApplication.java:315) [spring-boot-1.4.3.RELEASE.jar:1.4.3.RELEASE]
        at org.springframework.boot.SpringApplication.run(SpringApplication.java:1186) [spring-boot-1.4.3.RELEASE.jar:1.4.3.RELEASE]
        at org.springframework.boot.SpringApplication.run(SpringApplication.java:1175) [spring-boot-1.4.3.RELEASE.jar:1.4.3.RELEASE]
        at com.spring.AppleApplication.main(AppleApplication.java:13) [classes/:na]
    Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userRepository': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Validation failed for query for method public abstract java.util.List com.spring.controller.UserRepository.findById(java.lang.Integer)!
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1589) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:554) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:483) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:306) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:230) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:302) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:202) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.config.DependencyDescriptor.resolveCandidate(DependencyDescriptor.java:207) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:1136) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:1064) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:585) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        ... 19 common frames omitted
    Caused by: java.lang.IllegalArgumentException: Validation failed for query for method public abstract java.util.List com.spring.controller.UserRepository.findById(java.lang.Integer)!
        at org.springframework.data.jpa.repository.query.SimpleJpaQuery.validateQuery(SimpleJpaQuery.java:92) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        at org.springframework.data.jpa.repository.query.SimpleJpaQuery.<init>(SimpleJpaQuery.java:62) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        at org.springframework.data.jpa.repository.query.JpaQueryFactory.fromMethodWithQueryString(JpaQueryFactory.java:72) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        at org.springframework.data.jpa.repository.query.JpaQueryFactory.fromQueryAnnotation(JpaQueryFactory.java:53) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$DeclaredQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:144) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$CreateIfNotFoundQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:212) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$AbstractQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:77) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.<init>(RepositoryFactorySupport.java:435) ~[spring-data-commons-1.12.6.RELEASE.jar:na]
        at org.springframework.data.repository.core.support.RepositoryFactorySupport.getRepository(RepositoryFactorySupport.java:220) ~[spring-data-commons-1.12.6.RELEASE.jar:na]
        at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.initAndReturn(RepositoryFactoryBeanSupport.java:280) ~[spring-data-commons-1.12.6.RELEASE.jar:na]
        at org.springframework.data.repository.core.support.RepositoryFactoryBeanSupport.afterPropertiesSet(RepositoryFactoryBeanSupport.java:266) ~[spring-data-commons-1.12.6.RELEASE.jar:na]
        at org.springframework.data.jpa.repository.support.JpaRepositoryFactoryBean.afterPropertiesSet(JpaRepositoryFactoryBean.java:92) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1648) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1585) ~[spring-beans-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        ... 29 common frames omitted
    Caused by: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: users is not mapped [select id,name from users where id=:id]
        at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1679) ~[hibernate-entitymanager-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1602) ~[hibernate-entitymanager-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1608) ~[hibernate-entitymanager-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:294) ~[hibernate-entitymanager-5.0.11.Final.jar:5.0.11.Final]
        at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) ~[na:1.8.0_101]
        at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) ~[na:1.8.0_101]
        at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) ~[na:1.8.0_101]
        at java.lang.reflect.Method.invoke(Unknown Source) ~[na:1.8.0_101]
        at org.springframework.orm.jpa.ExtendedEntityManagerCreator$ExtendedEntityManagerInvocationHandler.invoke(ExtendedEntityManagerCreator.java:347) ~[spring-orm-4.3.5.RELEASE.jar:4.3.5.RELEASE]
        at com.sun.proxy.$Proxy73.createQuery(Unknown Source) ~[na:na]
        at org.springframework.data.jpa.repository.query.SimpleJpaQuery.validateQuery(SimpleJpaQuery.java:86) ~[spring-data-jpa-1.10.6.RELEASE.jar:na]
        ... 42 common frames omitted
    Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: users is not mapped [select id,name from users where id=:id]
        at org.hibernate.hql.internal.ast.QuerySyntaxException.generateQueryException(QuerySyntaxException.java:79) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:218) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:142) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:115) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:76) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:150) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.internal.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:302) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.internal.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:240) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.internal.SessionImpl.createQuery(SessionImpl.java:1894) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.jpa.spi.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:291) ~[hibernate-entitymanager-5.0.11.Final.jar:5.0.11.Final]
        ... 49 common frames omitted
    Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: users is not mapped
        at org.hibernate.hql.internal.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:171) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:91) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.ast.tree.FromClause.addFromElement(FromClause.java:76) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:321) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3687) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:3576) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:716) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:572) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:309) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:257) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:262) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:190) ~[hibernate-core-5.0.11.Final.jar:5.0.11.Final]
        ... 57 common frames omitted
    
    
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    • 0
    • 對於你、虚偽 普通会员 1楼

      在Spring Boot JPA中,通过findById()方法查询对象时,可能会出现以下几种问题:

      1. 模糊查询: 如果在主键列上使用了模糊查询(如findByEmail(String email)),则在获取匹配结果时,JPA会自动在查询结果中模糊匹配,即使查询条件为空或字符串不匹配。例如,如果你有一个名为users的表,其中包含一个名为email的列,你想查找所有电子邮件地址为example@example.com的用户,你可能会使用以下查询:

      java @Query("SELECT u FROM users u WHERE u.email = ?1") public List<User> findByEmail(@Param("email") String email);

      如果email为空,JPA将会返回所有匹配的用户,包括那些电子邮件地址为空的用户。这可能会导致性能问题,特别是在大型表或查询时。

      为避免这个问题,你可以使用@Param注解来指定查询参数的类型为字符串,如下所示:

      java @Query("SELECT u FROM users u WHERE u.email = :email") public List<User> findByEmail(@Param("email") String email, Object param);

      或者,你可以使用@Param注解来指定查询参数的类型为Email,如下所示:

      java @Query("SELECT u FROM users u WHERE u.email IS NULL OR u.email = :email") public List<User> findByEmail(@Param("email") String email, Object param);

      1. 特殊情况处理: 如果在主键列上使用了特定的逻辑表达式(如@Id注解、@GeneratedValue(strategy=GenerationType.AUTO)等),则在查询结果中,JPA会自动将主键映射到字段名中。例如,如果你有一个名为users的表,其中包含一个名为id的主键列,你想查找所有包含id=1的用户,你可能会使用以下查询:

      java @Query("SELECT u FROM users u WHERE u.id = ?1") public List<User> findById(@Param("id") int id);

      如果id为0,JPA将会返回所有匹配的用户,包括那些id=0的用户。这可能会导致性能问题,特别是在处理大量数据时。

      为避免这个问题,你可以使用@Param注解来指定查询参数的类型为整数,如下所示:

      java @Query("SELECT u FROM users u WHERE u.id = ?1") public List<User> findById(@Param("id") int id, Object param);

      或者,你可以使用@Param注解来指定查询参数的类型为自定义类,例如@Param(value = "id", type = Integer.class),如下所示:

      java @Query("SELECT u FROM users u WHERE u.id = ?1") public List<User> findById(@Param("id") Integer id, Object param);

      1. 参数传递问题: 在查询结果中,findById()方法接收的参数通常是一个Entity对象,该对象包含了查询结果的所有字段和属性。如果查询结果的字段名称和属性名称不匹配,或者属性的名称包含特殊字符,JPA可能会抛出PropertyNotFoundExceptionUnsupportedOperationException异常,这可能会影响查询结果的处理。

      为了避免这个问题,你可以使用@Query注解的query属性来指定查询参数的类型为Entity对象,如下所示:

      java @Query("SELECT u FROM users u WHERE u.id = ?1") public List<User> findById(@Param("id") Long id, Entity entity, Object param);

      这个例子中,entity参数应该是一个Entity对象,其中包含了查询结果的所有字段和属性,而param参数可以是任何有效的Java对象,包括其他Entity对象、字符串、数字、布尔值等。

      1. 并发问题: 如果在查询结果中包含多个主键值对,而且这些主键值对是在不同的事务中创建的,JPA可能会并发地将这些主键值对插入到数据库中。这可能会导致数据不一致或丢失,特别是在数据库有多个读写事务同时操作时。

      为了避免这个问题,你可以使用@EnableJpaRepositories注解来启用JpaRepository接口,该接口提供了一种方便的方式来管理和操作数据库中的对象,包括批量插入和删除操作。例如,你可以使用以下代码将查询结果插入到数据库:

      ```java @EnableJpaRepositories public class UserRepository {

         @Query("SELECT u FROM users u WHERE u.id = ?1")
         public List<User> findById(@Param("id") Long id) {
             // 将查询结果插入到数据库
             return repository.findAll();
         }
      

      } ```

      这个例子中,repository.findAll()方法会返回一个包含所有匹配结果的List<User>,并且在数据库中实现了JpaRepository接口的findAll()方法,可以用于并发地执行插入和删除操作。

      总的来说,通过使用@Param注解来指定查询参数的类型,以及启用JpaRepository接口,可以有效地处理查询结果中的主键值对,避免出现性能问题和数据不一致的问题。

    • 芃玉燕 普通会员 2楼

      在Spring Boot JPA中,通过findById()方法查询对象时,可能会出现以下几种问题:

      1. 模糊查询: 如果在主键列上使用了模糊查询(如findByEmail(String email)),则在获取匹配结果时,JPA会自动在查询结果中模糊匹配,即使查询条件为空或字符串不匹配。例如,如果你有一个名为users的表,其中包含一个名为email的列,你想查找所有电子邮件地址为example@example.com的用户,你可能会使用以下查询:

      java @Query("SELECT u FROM users u WHERE u.email = ?1") public List<User> findByEmail(@Param("email") String email);

      如果email为空,JPA将会返回所有匹配的用户,包括那些电子邮件地址为空的用户。这可能会导致性能问题,特别是在大型表或查询时。

      为避免这个问题,你可以使用@Param注解来指定查询参数的类型为字符串,如下所示:

      java @Query("SELECT u FROM users u WHERE u.email = :email") public List<User> findByEmail(@Param("email") String email, Object param);

      或者,你可以使用@Param注解来指定查询参数的类型为Email,如下所示:

      java @Query("SELECT u FROM users u WHERE u.email IS NULL OR u.email = :email") public List<User> findByEmail(@Param("email") String email, Object param);

      1. 特殊情况处理: 如果在主键列上使用了特定的逻辑表达式(如@Id注解、@GeneratedValue(strategy=GenerationType.AUTO)等),则在查询结果中,JPA会自动将主键映射到字段名中。例如,如果你有一个名为users的表,其中包含一个名为id的主键列,你想查找所有包含id=1的用户,你可能会使用以下查询:

      java @Query("SELECT u FROM users u WHERE u.id = ?1") public List<User> findById(@Param("id") int id);

      如果id为0,JPA将会返回所有匹配的用户,包括那些id=0的用户。这可能会导致性能问题,特别是在处理大量数据时。

      为避免这个问题,你可以使用@Param注解来指定查询参数的类型为整数,如下所示:

      java @Query("SELECT u FROM users u WHERE u.id = ?1") public List<User> findById(@Param("id") int id, Object param);

      或者,你可以使用@Param注解来指定查询参数的类型为自定义类,例如@Param(value = "id", type = Integer.class),如下所示:

      java @Query("SELECT u FROM users u WHERE u.id = ?1") public List<User> findById(@Param("id") Integer id, Object param);

      1. 参数传递问题: 在查询结果中,findById()方法接收的参数通常是一个Entity对象,该对象包含了查询结果的所有字段和属性。如果查询结果的字段名称和属性名称不匹配,或者属性的名称包含特殊字符,JPA可能会抛出PropertyNotFoundExceptionUnsupportedOperationException异常,这可能会影响查询结果的处理。

      为了避免这个问题,你可以使用@Query注解的query属性来指定查询参数的类型为Entity对象,如下所示:

      java @Query("SELECT u FROM users u WHERE u.id = ?1") public List<User> findById(@Param("id") Long id, Entity entity, Object param);

      这个例子中,entity参数应该是一个Entity对象,其中包含了查询结果的所有字段和属性,而param参数可以是任何有效的Java对象,包括其他Entity对象、字符串、数字、布尔值等。

      1. 并发问题: 如果在查询结果中包含多个主键值对,而且这些主键值对是在不同的事务中创建的,JPA可能会并发地将这些主键值对插入到数据库中。这可能会导致数据不一致或丢失,特别是在数据库有多个读写事务同时操作时。

      为了避免这个问题,你可以使用@EnableJpaRepositories注解来启用JpaRepository接口,该接口提供了一种方便的方式来管理和操作数据库中的对象,包括批量插入和删除操作。例如,你可以使用以下代码将查询结果插入到数据库:

      ```java @EnableJpaRepositories public class UserRepository {

         @Query("SELECT u FROM users u WHERE u.id = ?1")
         public List<User> findById(@Param("id") Long id) {
             // 将查询结果插入到数据库
             return repository.findAll();
         }
      

      } ```

      这个例子中,repository.findAll()方法会返回一个包含所有匹配结果的List<User>,并且在数据库中实现了JpaRepository接口的findAll()方法,可以用于并发地执行插入和删除操作。

      总的来说,通过使用@Param注解来指定查询参数的类型,以及启用JpaRepository接口,可以有效地处理查询结果中的主键值对,避免出现性能问题和数据不一致的问题。

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