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    how the value of open in dropdown of react-bootstrap change?
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    1,i read in the react - the source code of the bootstrap.But I feel very confused, the open value is how change?The following code

    dropdown.js
    Dropdown.propTypes = propTypes;
    Dropdown.defaultProps = defaultProps;
    setBsClass('dropdown', Dropdown);
    const UncontrolledDropdown = uncontrollable(Dropdown, { open: 'onToggle' });
    UncontrolledDropdown.Toggle = DropdownToggle;
    UncontrolledDropdown.Menu = DropdownMenu;
    export default UncontrolledDropdown;

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    • 仙女味＞的＜小可耐●０● 普通会员 1楼

      In React Bootstrap, the value of the open prop in a dropdown component changes when the value of the selected prop changes. The selected prop determines whether the dropdown is open or closed. The open prop determines whether the dropdown is currently open or not. Here's an example of how the open prop works in a React Bootstrap dropdown component: ```javascript

      {selected === "option1" ? ( ) : ( )}

      ```

      In this example, the selected prop is set to "option1", which means the dropdown is currently open. The dropdown-menu component displays the options for "option1", and the selected prop determines whether the selected option is displayed or not. If selected is "option1", the dropdown-menu will display the ul element containing the li elements for "Link 1" and "Link 2". If selected is not "option1", the dropdown-menu will not display any options. The value of the open prop can also be set to false to close the dropdown. For example: ```javascript

      {selected === "option1" ? ( ) : ( )}

      ```

      In this example, the open prop is set to false, which means the dropdown is currently closed. The dropdown-menu component will not display any options, and the selected prop will not be used.

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