const router = [
    {
        path: '/hello',
        icon: 'hammer',
        name: 'hello',
        title: '你好',
        children: [
            { path: 'index', title: '你好', name: 'hello_index' },
            { path: 'index1', title: '你好1', name: 'hello_index1' }
        ]
    },
    {
        path: '/hello1',
        icon: 'hammer',
        name: 'hello1',
        title: '你好',
        children: [
            { path: 'index2', title: '你好2', name: 'hello_index2' },
            { path: 'index3', title: '你好3', name: 'hello_index3' },
            { path: 'index4', title: '你好3', name: 'hello_index4' }
        ]
    },
    {
        path: '/hello2',
        icon: 'hammer',
        name: 'hello2',
        title: '你好',
        children: [
            { path: 'index4', title: '你好4', name: 'hello_index4' },
            { path: 'index5', title: '你好5', name: 'hello_index5' }
        ]
    }
]
let routernone = [
    {
        path: '/hello2',
        children: []
    },
    {
        path: '/hello1',
        children: [
            'index2', 'index3'
        ]
    }
];

请问如何在 router 以 routernone 为规则 筛选出新数组，routernone中表明，不取path为'/hello2'的，不取path为'/hello1'的children中 path为index2的和path为index3的，