有以下数据：
 let a = new Set([
    {
        'categoryId': 1,
        'categoryIdLevelOne': 750611334,
        'categoryIdLevelThree': 750611336,
        'categoryIdLevelTwo': 750611335,
        'id': 2697,
        'level': 3,
        'shopId': 12430,
        'skipLayoutFlag': false,
        'status': 1
    },
    {
        'categoryId': 2,
        'categoryIdLevelOne': 750611472,
        'categoryIdLevelTwo': 750611473,
        'id': 2701,
        'level': 2,
        'shopId': 12430,
        'skipLayoutFlag': false,
        'status': 2
    },
    {
        'categoryId': 3,
        'categoryIdLevelOne': 750611487,
        'categoryIdLevelTwo': 750611488,
        'id': 2702,
        'level': 2,
        'shopId': 12430,
        'skipLayoutFlag': false,
        'status': 1
    }
])
let b = new Set([
    {
        'categoryId': 2,
        'categoryIdLevelOne': 750611334,
        'categoryIdLevelThree': 750611336,
        'categoryIdLevelTwo': 750611335,
        'id': 2697,
        'level': 3,
        'shopId': 12430,
        'skipLayoutFlag': false,
        'status': 1
    },
    {
        'categoryId': 3,
        'categoryIdLevelOne': 750611472,
        'categoryIdLevelTwo': 750611473,
        'id': 2701,
        'level': 2,
        'shopId': 12430,
        'skipLayoutFlag': false,
        'status': 2
    },
    {
        'categoryId': 4,
        'categoryIdLevelOne': 750611487,
        'categoryIdLevelTwo': 750611488,
        'id': 2702,
        'level': 2,
        'shopId': 12430,
        'skipLayoutFlag': false,
        'status': 1
    }
])



  以上数据中，如何根据categoryId求交集：
  let union = [...new Set([...a, ...b])] 
        
  let intersect = [...new Set([...a].filter(x => b.has(x)))]
    
  intersect结果为[]！
  如果数据是：
  let a=new Set([1,2,3]);
  let b=new Set([4,3,2]);  
  结果是我想要的。