假设我们有一个类列表，其中包含子类和父类的关系，它们是以json格式存储的，如下所示：

json [ {"name": "A", "parent": null}, {"name": "B", "parent": "A"}, {"name": "C", "parent": "B"}, {"name": "D", "parent": "A"}, {"name": "E", "parent": "C"}, {"name": "F", "parent": "D"} ]

现在我们想要将这个列表转换为以子类为根节点，向上查找所有父类的树形结构。例如，如果我们指定子类"E"，则结果应为：

json { "name": "E", "children": [ { "name": "C", "children": [ { "name": "B", "children": [ { "name": "A", "children": [] } ] } ] } ] }

以下是一个Python示例来实现这个转换：

```python import json

class_tree = [ {"name": "A", "parent": None}, {"name": "B", "parent": "A"}, {"name": "C", "parent": "B"}, {"name": "D", "parent": "A"}, {"name": "E", "parent": "C"}, {"name": "F", "parent": "D"} ]

def build_class_hierarchy(cls_name, class_tree): node = next((item for item in class_tree if item["name"] == cls_name), None) if not node: return None

hierarchy = {"name": node["name"], "children": []}
parent_name = node["parent"]

while parent_name is not None:
    parent = next((item for item in class_tree if item["name"] == parent_name), None)
    if parent:
        hierarchy["children"].append({"name": parent["name"], "children": []})
        parent_name = parent["parent"]
    else:
        break

return hierarchy

指定子类"E"

target_cls = "E" result = build_class_hierarchy(target_cls, class_tree)

print(json.dumps(result, indent=2)) ```

注意：这个例子中没有对循环引用或者层级过深的情况做处理，实际使用时可能需要根据实际情况进行调整。