写了个函数实现递归的查找文件或者文件夹，但是返回值一值为None,代码如下：

#!/usr/bin/env python3
# -*- coding: utf-8 -*-

import os
import argparse
from collections import deque


def findFile1(path, file):
    '''To implent the simple functions like linux command -- find.'''
    # Depth First Search
    with os.scandir(path) as entryDir:
        for entry in entryDir:
            if entry.is_file(follow_symlinks=True) and entry.name == file:
                print(entry.path)
                return entry.path  # print能正常输出结果，但是return却是None，为什么？
            if entry.is_dir(follow_symlinks=True):
                if entry.name == file:
                    print(entry.path)
                    return entry.path
                else:
                    findFile1(path=entry.path, file=file)
                    # return findFile1(path=entry.path, file=file) 这里用return的时候print的输出都没了，这是为什么

if __name__ == '__main__':
    parser = argparse.ArgumentParser('To implent the simple functions like linux command -- find.')
    parser.add_argument('-p', '--path', type=str, help='the root directory to find file.')
    parser.add_argument('-f', '--file', type=str, help='the file or dir to find.')
    args = vars(parser.parse_args())
    path = args['path']
    file = args['file']

    res = findFile1(path, file)
    print(res)

运行函数：

$ python D:\scripts\funny\find_file.py -p D:\sublime_coding -f notes.py
D:\sublime_coding\matplotlib\notes.py
None

#当递归那一步使用 return findFile1(path=entry.path, file=file) 时，返回结果直接为None了，print输出都没了
$ python D:\scripts\funny\find_file.py -p D:\sublime_coding -f notes.py
None

请教问题出在哪里，谢谢！